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Tuesday 12 February 2013

Real World Applications

Week 1 Assignment Real World Applications

two-dimensional 126

January XX, 20XX

Real World Applications
In lieu of not having a book on time to complete this assignment, I took the proactive approach to researching and solving the questions we needed to respond to. Upon my becomeings, because the question had recurrent additions, that tells us that in gild to solve the question, we must book an arithmetic sequence.
There is a value in consciousness how to comprehend and pay arithmetic sequence (otherwise known as arithmetic progression) in the real world, especially when trying to apply it to things such as Microsoft leap unwrap. Ive provided an example of doing it in Excel in the long fashion along with doing it by the equation.
The Problem
A person hired a firm to build a CB radio tower. The firm charges $100 for labor for the beginning(a) 10 feet. After that, the comprise of the labor for each succeeding 10 feet is $25 more than the preceding 10 feet. That is, the next 10 feet will cost $125, the next 10 feet will cost $150, etc. How much will it cost to build a 90-foot tower?
The Thought Process
The upfront cost the firm charges for the first 10 feet is $100. For each succeeding 10 feet, the cost is $25 more than the preceding 10 feet. The total number of measure (or terms as used in the example) is n=9 (90/10=9). The common cost difference is d=$25.

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In this case, the first term, which means the first 10 feet be a1=$100. The last term is what we are trying to get. That is an=a9. Our goal is to find out what n equals here. By using the formula provided at bottom the text and found online when researching arithmetic sequence, we can find out the nth term of the sequence.
an=a1+(n-1)d
a9=100+(9-1)(25)
a9=100+(8)(25)
a9=100+200
a9=300
outright we need to figure out the sum of the sequence from a1 to a9. at a lower place is the work to get the solution.
Sn=n(a1+a9)
2
Sn=9(100+300)
2
Sn=9(400)
2
Sn=$3600/2
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